Base | Representation |
---|---|
bin | 11110100011110011000111… |
… | …010100000011100110011001 |
3 | 122121212122122212112222200202 |
4 | 132203303013110003212121 |
5 | 120104013142400100131 |
6 | 1153503102324511545 |
7 | 40211120325116156 |
oct | 3643630724034631 |
9 | 577778585488622 |
10 | 134401460550041 |
11 | 39908380707043 |
12 | 130a7aa124b5b5 |
13 | 59cc00747ab39 |
14 | 25290cb65522d |
15 | 10811552a2bcb |
hex | 7a3cc7503999 |
134401460550041 has 2 divisors, whose sum is σ = 134401460550042. Its totient is φ = 134401460550040.
The previous prime is 134401460550017. The next prime is 134401460550107. The reversal of 134401460550041 is 140055064104431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130505491210000 + 3895969340041 = 11423900^2 + 1973821^2 .
It is a cyclic number.
It is not a de Polignac number, because 134401460550041 - 214 = 134401460533657 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134401460549977 and 134401460550004.
It is not a weakly prime, because it can be changed into another prime (134401460540041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200730275020 + 67200730275021.
It is an arithmetic number, because the mean of its divisors is an integer number (67200730275021).
Almost surely, 2134401460550041 is an apocalyptic number.
It is an amenable number.
134401460550041 is a deficient number, since it is larger than the sum of its proper divisors (1).
134401460550041 is an equidigital number, since it uses as much as digits as its factorization.
134401460550041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 38.
The spelling of 134401460550041 in words is "one hundred thirty-four trillion, four hundred one billion, four hundred sixty million, five hundred fifty thousand, forty-one".
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