13440214233 has 12 divisors (see below), whose sum is σ = 19483731748. Its totient is φ = 8927794080.

The previous prime is 13440214231. The next prime is 13440214247. The reversal of 13440214233 is 33241204431.

13440214233 is a `hidden beast` number, since 1 + 3 + 440 + 214 + 2 + 3 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 4214995929 + 9225218304 = 64923^2 + 96048^2 .

It is not a de Polignac number, because 13440214233 - 2¹ = 13440214231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13440214197 and 13440214206.

It is not an unprimeable number, because it can be changed into a prime (13440214231) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2693098 + ... + 2698083.

Almost surely, 2^13440214233 is an apocalyptic number.

It is an amenable number.

13440214233 is a deficient number, since it is larger than the sum of its proper divisors (6043517515).

13440214233 is a wasteful number, since it uses less digits than its factorization.

13440214233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5391464 (or 5391461 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13440214233 its reverse (33241204431), we get a palindrome (46681418664).

The spelling of 13440214233 in words is "thirteen billion, four hundred forty million, two hundred fourteen thousand, two hundred thirty-three".