Base | Representation |
---|---|
bin | 11001000010001100… |
… | …11001000011101010 |
3 | 1021200200011012100011 |
4 | 30201012121003222 |
5 | 210011144204024 |
6 | 10101354402134 |
7 | 654030013642 |
oct | 144106310352 |
9 | 37620135304 |
10 | 13440225514 |
11 | 57777253a1 |
12 | 273113034a |
13 | 1362658681 |
14 | 917001522 |
15 | 539e0e094 |
hex | 3211990ea |
13440225514 has 4 divisors (see below), whose sum is σ = 20160338274. Its totient is φ = 6720112756.
The previous prime is 13440225511. The next prime is 13440225563. The reversal of 13440225514 is 41552204431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12368776225 + 1071449289 = 111215^2 + 32733^2 .
It is not an unprimeable number, because it can be changed into a prime (13440225511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360056377 + ... + 3360056380.
Almost surely, 213440225514 is an apocalyptic number.
13440225514 is a deficient number, since it is larger than the sum of its proper divisors (6720112760).
13440225514 is an equidigital number, since it uses as much as digits as its factorization.
13440225514 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6720112759.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 13440225514 its reverse (41552204431), we get a palindrome (54992429945).
The spelling of 13440225514 in words is "thirteen billion, four hundred forty million, two hundred twenty-five thousand, five hundred fourteen".
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