13440241 has 2 divisors, whose sum is σ = 13440242. Its totient is φ = 13440240.

The previous prime is 13440233. The next prime is 13440269. The reversal of 13440241 is 14204431.

13440241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12047841 + 1392400 = 3471^2 + 1180^2 .

It is a cyclic number.

It is not a de Polignac number, because 13440241 - 2³ = 13440233 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13440221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720120 + 6720121.

It is an arithmetic number, because the mean of its divisors is an integer number (6720121).

Almost surely, 2^13440241 is an apocalyptic number.

It is an amenable number.

13440241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440241 is an equidigital number, since it uses as much as digits as its factorization.

13440241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 13440241 is about 3666.0934248870. The cubic root of 13440241 is about 237.7582992183.

Adding to 13440241 its reverse (14204431), we get a palindrome (27644672).

The spelling of 13440241 in words is "thirteen million, four hundred forty thousand, two hundred forty-one".