Base | Representation |
---|---|
bin | 10011100011101110000… |
… | …110010110110101000101 |
3 | 11202111011101002201201220 |
4 | 103203232012112311011 |
5 | 134010030224041013 |
6 | 2505234124110553 |
7 | 166050115146654 |
oct | 23435606266505 |
9 | 4674141081656 |
10 | 1344024440133 |
11 | 478aa7837711 |
12 | 198593095459 |
13 | 99982b7780b |
14 | 490a042d19b |
15 | 24e63dadb23 |
hex | 138ee196d45 |
1344024440133 has 16 divisors (see below), whose sum is σ = 1802042424000. Its totient is φ = 891011975040.
The previous prime is 1344024440119. The next prime is 1344024440149. The reversal of 1344024440133 is 3310444204431.
It is not a de Polignac number, because 1344024440133 - 24 = 1344024440117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1344024440094 and 1344024440103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1344024442133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10196673 + ... + 10327641.
It is an arithmetic number, because the mean of its divisors is an integer number (112627651500).
Almost surely, 21344024440133 is an apocalyptic number.
It is an amenable number.
1344024440133 is a deficient number, since it is larger than the sum of its proper divisors (458017983867).
1344024440133 is a wasteful number, since it uses less digits than its factorization.
1344024440133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150052.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 1344024440133 its reverse (3310444204431), we get a palindrome (4654468644564).
The spelling of 1344024440133 in words is "one trillion, three hundred forty-four billion, twenty-four million, four hundred forty thousand, one hundred thirty-three".
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