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13440302041 = 67200601523
BaseRepresentation
bin11001000010001101…
…01011101111011001
31021200200022002022111
430201012223233121
5210011204131131
610101400152321
7654030453025
oct144106535731
937620262274
1013440302041
115777777941
1227311686a1
13136268445a
14917021385
15539e26ab1
hex3211abbd9

13440302041 has 4 divisors (see below), whose sum is σ = 13640903632. Its totient is φ = 13239700452.

The previous prime is 13440302021. The next prime is 13440302047. The reversal of 13440302041 is 14020304431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13440302041 - 211 = 13440299993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13440302047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100300695 + ... + 100300828.

It is an arithmetic number, because the mean of its divisors is an integer number (3410225908).

Almost surely, 213440302041 is an apocalyptic number.

It is an amenable number.

13440302041 is a deficient number, since it is larger than the sum of its proper divisors (200601591).

13440302041 is an equidigital number, since it uses as much as digits as its factorization.

13440302041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200601590.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13440302041 its reverse (14020304431), we get a palindrome (27460606472).

The spelling of 13440302041 in words is "thirteen billion, four hundred forty million, three hundred two thousand, forty-one".

Divisors: 1 67 200601523 13440302041