Base | Representation |
---|---|
bin | 111110100101100010… |
… | …0010101100101100011 |
3 | 110211220210201212112222 |
4 | 1331023010111211203 |
5 | 4200224233224441 |
6 | 141424415341255 |
7 | 12465433113062 |
oct | 1751304254543 |
9 | 424823655488 |
10 | 134403414371 |
11 | 52000250566 |
12 | 2206b52182b |
13 | c89c261975 |
14 | 67102321d9 |
15 | 3769723d4b |
hex | 1f4b115963 |
134403414371 has 4 divisors (see below), whose sum is σ = 135259487232. Its totient is φ = 133547341512.
The previous prime is 134403414367. The next prime is 134403414373. The reversal of 134403414371 is 173414304431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 173414304431 = 211151 ⋅821281.
It is a cyclic number.
It is not a de Polignac number, because 134403414371 - 22 = 134403414367 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134403414373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 428036195 + ... + 428036508.
It is an arithmetic number, because the mean of its divisors is an integer number (33814871808).
Almost surely, 2134403414371 is an apocalyptic number.
134403414371 is a deficient number, since it is larger than the sum of its proper divisors (856072861).
134403414371 is an equidigital number, since it uses as much as digits as its factorization.
134403414371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 856072860.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 134403414371 in words is "one hundred thirty-four billion, four hundred three million, four hundred fourteen thousand, three hundred seventy-one".
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