Base | Representation |
---|---|
bin | 11001000010001110… |
… | …00110111010100011 |
3 | 1021200200111201222221 |
4 | 30201013012322203 |
5 | 210011221211342 |
6 | 10101402411511 |
7 | 654031425364 |
oct | 144107067243 |
9 | 37620451887 |
10 | 13440413347 |
11 | 5777843529 |
12 | 2731200b97 |
13 | 13626c300a |
14 | 91704db6b |
15 | 539e49a67 |
hex | 3211c6ea3 |
13440413347 has 2 divisors, whose sum is σ = 13440413348. Its totient is φ = 13440413346.
The previous prime is 13440413309. The next prime is 13440413369. The reversal of 13440413347 is 74331404431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13440413347 - 27 = 13440413219 is a prime.
It is not a weakly prime, because it can be changed into another prime (13440413447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720206673 + 6720206674.
It is an arithmetic number, because the mean of its divisors is an integer number (6720206674).
Almost surely, 213440413347 is an apocalyptic number.
13440413347 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440413347 is an equidigital number, since it uses as much as digits as its factorization.
13440413347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 34.
Adding to 13440413347 its reverse (74331404431), we get a palindrome (87771817778).
The spelling of 13440413347 in words is "thirteen billion, four hundred forty million, four hundred thirteen thousand, three hundred forty-seven".
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