13440433 has 4 divisors (see below), whose sum is σ = 13500928. Its totient is φ = 13379940.

The previous prime is 13440431. The next prime is 13440437. The reversal of 13440433 is 33404431.

13440433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33404431 = 5717 ⋅5843.

It is a cyclic number.

It is not a de Polignac number, because 13440433 - 2¹ = 13440431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13440431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29913 + ... + 30358.

It is an arithmetic number, because the mean of its divisors is an integer number (3375232).

Almost surely, 2^13440433 is an apocalyptic number.

It is an amenable number.

13440433 is a deficient number, since it is larger than the sum of its proper divisors (60495).

13440433 is an equidigital number, since it uses as much as digits as its factorization.

13440433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60494.

The product of its (nonzero) digits is 1728, while the sum is 22.

The square root of 13440433 is about 3666.1196107056. The cubic root of 13440433 is about 237.7594313750.

Adding to 13440433 its reverse (33404431), we get a palindrome (46844864).

The spelling of 13440433 in words is "thirteen million, four hundred forty thousand, four hundred thirty-three".