Base | Representation |
---|---|
bin | 11001000010010010… |
… | …11011000101000011 |
3 | 1021200201122120110222 |
4 | 30201021123011003 |
5 | 210011400121402 |
6 | 10101423413255 |
7 | 654036533615 |
oct | 144111330503 |
9 | 37621576428 |
10 | 13441020227 |
11 | 5778118488 |
12 | 273145422b |
13 | 136287630b |
14 | 91716adb5 |
15 | 53a0197a2 |
hex | 32125b143 |
13441020227 has 2 divisors, whose sum is σ = 13441020228. Its totient is φ = 13441020226.
The previous prime is 13441020181. The next prime is 13441020239. The reversal of 13441020227 is 72202014431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13441020227 - 214 = 13441003843 is a prime.
It is a super-2 number, since 2×134410202272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13441020196 and 13441020205.
It is not a weakly prime, because it can be changed into another prime (13441029227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720510113 + 6720510114.
It is an arithmetic number, because the mean of its divisors is an integer number (6720510114).
Almost surely, 213441020227 is an apocalyptic number.
13441020227 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441020227 is an equidigital number, since it uses as much as digits as its factorization.
13441020227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 26.
Adding to 13441020227 its reverse (72202014431), we get a palindrome (85643034658).
The spelling of 13441020227 in words is "thirteen billion, four hundred forty-one million, twenty thousand, two hundred twenty-seven".
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