Base | Representation |
---|---|
bin | 1100001110011000011011… |
… | …1000010000010010111011 |
3 | 1202120222010102102102122101 |
4 | 3003212012320100102323 |
5 | 3230210102141003224 |
6 | 44330450441204231 |
7 | 2555044565120443 |
oct | 303460670202273 |
9 | 52528112372571 |
10 | 13441215562939 |
11 | 43124298565aa |
12 | 1610bb7a90677 |
13 | 76666915c108 |
14 | 3467b5db7123 |
15 | 184984629044 |
hex | c3986e104bb |
13441215562939 has 2 divisors, whose sum is σ = 13441215562940. Its totient is φ = 13441215562938.
The previous prime is 13441215562913. The next prime is 13441215562991. The reversal of 13441215562939 is 93926551214431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13441215562939 - 29 = 13441215562427 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13441215562939.
It is not a weakly prime, because it can be changed into another prime (13441215562639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720607781469 + 6720607781470.
It is an arithmetic number, because the mean of its divisors is an integer number (6720607781470).
Almost surely, 213441215562939 is an apocalyptic number.
13441215562939 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441215562939 is an equidigital number, since it uses as much as digits as its factorization.
13441215562939 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6998400, while the sum is 55.
The spelling of 13441215562939 in words is "thirteen trillion, four hundred forty-one billion, two hundred fifteen million, five hundred sixty-two thousand, nine hundred thirty-nine".
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