Base | Representation |
---|---|
bin | 1100001110011010000110… |
… | …0100011110010010011001 |
3 | 1202121000021122000222202020 |
4 | 3003212201210132102121 |
5 | 3230212011310042301 |
6 | 44331003115125053 |
7 | 2555061643262604 |
oct | 303464144362231 |
9 | 52530248028666 |
10 | 13441663362201 |
11 | 43126395a9838 |
12 | 1611101a43789 |
13 | 76670ab681a9 |
14 | 34681966133b |
15 | 1849adad0436 |
hex | c39a191e499 |
13441663362201 has 4 divisors (see below), whose sum is σ = 17922217816272. Its totient is φ = 8961108908132.
The previous prime is 13441663362187. The next prime is 13441663362203. The reversal of 13441663362201 is 10226336614431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13441663362201 - 234 = 13424483493017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13441663362203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240277227031 + ... + 2240277227036.
It is an arithmetic number, because the mean of its divisors is an integer number (4480554454068).
Almost surely, 213441663362201 is an apocalyptic number.
It is an amenable number.
13441663362201 is a deficient number, since it is larger than the sum of its proper divisors (4480554454071).
13441663362201 is an equidigital number, since it uses as much as digits as its factorization.
13441663362201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4480554454070.
The product of its (nonzero) digits is 373248, while the sum is 42.
Adding to 13441663362201 its reverse (10226336614431), we get a palindrome (23667999976632).
The spelling of 13441663362201 in words is "thirteen trillion, four hundred forty-one billion, six hundred sixty-three million, three hundred sixty-two thousand, two hundred one".
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