Base | Representation |
---|---|
bin | 10011100011111000111… |
… | …000110100111110000011 |
3 | 11202111121222200121220211 |
4 | 103203320320310332003 |
5 | 134010413043133242 |
6 | 2505304111414551 |
7 | 166054443512653 |
oct | 23437070647603 |
9 | 4674558617824 |
10 | 1344205442947 |
11 | 47908aa24814 |
12 | 198623824457 |
13 | 999b150cc83 |
14 | 490ba4a8363 |
15 | 24e74c14317 |
hex | 138f8e34f83 |
1344205442947 has 2 divisors, whose sum is σ = 1344205442948. Its totient is φ = 1344205442946.
The previous prime is 1344205442941. The next prime is 1344205442977. The reversal of 1344205442947 is 7492445024431.
It is a weak prime.
It is an emirp because it is prime and its reverse (7492445024431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344205442947 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1344205442947.
It is not a weakly prime, because it can be changed into another prime (1344205442941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672102721473 + 672102721474.
It is an arithmetic number, because the mean of its divisors is an integer number (672102721474).
Almost surely, 21344205442947 is an apocalyptic number.
1344205442947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344205442947 is an equidigital number, since it uses as much as digits as its factorization.
1344205442947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3870720, while the sum is 49.
The spelling of 1344205442947 in words is "one trillion, three hundred forty-four billion, two hundred five million, four hundred forty-two thousand, nine hundred forty-seven".
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