13442062531 has 4 divisors (see below), whose sum is σ = 13462036552. Its totient is φ = 13422088512.

The previous prime is 13442062511. The next prime is 13442062567. The reversal of 13442062531 is 13526024431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13442062531 - 2²¹ = 13439965379 is a prime.

It is a super-2 number, since 2×13442062531² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13442062493 and 13442062502.

It is not an unprimeable number, because it can be changed into a prime (13442062511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9986001 + ... + 9987346.

It is an arithmetic number, because the mean of its divisors is an integer number (3365509138).

Almost surely, 2^13442062531 is an apocalyptic number.

13442062531 is a deficient number, since it is larger than the sum of its proper divisors (19974021).

13442062531 is an equidigital number, since it uses as much as digits as its factorization.

13442062531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19974020.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13442062531 its reverse (13526024431), we get a palindrome (26968086962).

The spelling of 13442062531 in words is "thirteen billion, four hundred forty-two million, sixty-two thousand, five hundred thirty-one".