Base | Representation |
---|---|
bin | 1100001110011011110110… |
… | …0101100100010101000101 |
3 | 1202121001111101111221200020 |
4 | 3003212331211210111011 |
5 | 3230213442123124031 |
6 | 44331121510005353 |
7 | 2555106411523641 |
oct | 303467545442505 |
9 | 52531441457606 |
10 | 13442133411141 |
11 | 431285a969536 |
12 | 1611213346859 |
13 | 766784364666 |
14 | 346861c5bc21 |
15 | 1849d9ece096 |
hex | c39bd964545 |
13442133411141 has 16 divisors (see below), whose sum is σ = 18512944857600. Its totient is φ = 8666745370560.
The previous prime is 13442133411059. The next prime is 13442133411143. The reversal of 13442133411141 is 14111433124431.
13442133411141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13442133411141 - 237 = 13304694457669 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13442133411143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46511550 + ... + 46799663.
It is an arithmetic number, because the mean of its divisors is an integer number (1157059053600).
Almost surely, 213442133411141 is an apocalyptic number.
It is an amenable number.
13442133411141 is a deficient number, since it is larger than the sum of its proper divisors (5070811446459).
13442133411141 is a wasteful number, since it uses less digits than its factorization.
13442133411141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93312796.
The product of its digits is 13824, while the sum is 33.
Adding to 13442133411141 its reverse (14111433124431), we get a palindrome (27553566535572).
The spelling of 13442133411141 in words is "thirteen trillion, four hundred forty-two billion, one hundred thirty-three million, four hundred eleven thousand, one hundred forty-one".
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