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134422100121242 = 267211050060621
BaseRepresentation
bin11110100100000110010101…
…100001110001011010011010
3122121221121221021112211200202
4132210012111201301122122
5120104332430112334432
61153520354342302202
740212450644433143
oct3644062541613232
9577847837484622
10134422100121242
11399161021613aa
12130abaa1427962
135a00c464c796b
14252a0c8864aca
151081962256462
hex7a419587169a

134422100121242 has 4 divisors (see below), whose sum is σ = 201633150181866. Its totient is φ = 67211050060620.

The previous prime is 134422100121233. The next prime is 134422100121269. The reversal of 134422100121242 is 242121001224431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 133043098493761 + 1379001627481 = 11534431^2 + 1174309^2 .

It is a super-2 number, since 2×1344221001212422 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33605525030309 + ... + 33605525030312.

Almost surely, 2134422100121242 is an apocalyptic number.

134422100121242 is a deficient number, since it is larger than the sum of its proper divisors (67211050060624).

134422100121242 is an equidigital number, since it uses as much as digits as its factorization.

134422100121242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67211050060623.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 134422100121242 its reverse (242121001224431), we get a palindrome (376543101345673).

The spelling of 134422100121242 in words is "one hundred thirty-four trillion, four hundred twenty-two billion, one hundred million, one hundred twenty-one thousand, two hundred forty-two".

Divisors: 1 2 67211050060621 134422100121242