Base | Representation |
---|---|
bin | 11110100100000110010101… |
… | …100001110001011010011010 |
3 | 122121221121221021112211200202 |
4 | 132210012111201301122122 |
5 | 120104332430112334432 |
6 | 1153520354342302202 |
7 | 40212450644433143 |
oct | 3644062541613232 |
9 | 577847837484622 |
10 | 134422100121242 |
11 | 399161021613aa |
12 | 130abaa1427962 |
13 | 5a00c464c796b |
14 | 252a0c8864aca |
15 | 1081962256462 |
hex | 7a419587169a |
134422100121242 has 4 divisors (see below), whose sum is σ = 201633150181866. Its totient is φ = 67211050060620.
The previous prime is 134422100121233. The next prime is 134422100121269. The reversal of 134422100121242 is 242121001224431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 133043098493761 + 1379001627481 = 11534431^2 + 1174309^2 .
It is a super-2 number, since 2×1344221001212422 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33605525030309 + ... + 33605525030312.
Almost surely, 2134422100121242 is an apocalyptic number.
134422100121242 is a deficient number, since it is larger than the sum of its proper divisors (67211050060624).
134422100121242 is an equidigital number, since it uses as much as digits as its factorization.
134422100121242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67211050060623.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 134422100121242 its reverse (242121001224431), we get a palindrome (376543101345673).
The spelling of 134422100121242 in words is "one hundred thirty-four trillion, four hundred twenty-two billion, one hundred million, one hundred twenty-one thousand, two hundred forty-two".
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