Base | Representation |
---|---|
bin | 11001000010011100… |
… | …01000010111100011 |
3 | 1021200210222021022122 |
4 | 30201032020113203 |
5 | 210012204114212 |
6 | 10101510054455 |
7 | 654053163536 |
oct | 144116102743 |
9 | 37623867278 |
10 | 13442254307 |
11 | 5778890689 |
12 | 273194a42b |
13 | 1362bb8c41 |
14 | 9173aca1d |
15 | 53a1b0272 |
hex | 3213885e3 |
13442254307 has 2 divisors, whose sum is σ = 13442254308. Its totient is φ = 13442254306.
The previous prime is 13442254303. The next prime is 13442254337. The reversal of 13442254307 is 70345224431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13442254307 - 22 = 13442254303 is a prime.
It is not a weakly prime, because it can be changed into another prime (13442254303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721127153 + 6721127154.
It is an arithmetic number, because the mean of its divisors is an integer number (6721127154).
Almost surely, 213442254307 is an apocalyptic number.
13442254307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13442254307 is an equidigital number, since it uses as much as digits as its factorization.
13442254307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 35.
Adding to 13442254307 its reverse (70345224431), we get a palindrome (83787478738).
The spelling of 13442254307 in words is "thirteen billion, four hundred forty-two million, two hundred fifty-four thousand, three hundred seven".
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