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134422644011 = 503267241837
BaseRepresentation
bin111110100110000110…
…1101100010100101011
3110211222010220211122212
41331030031230110223
54200244144102021
6141430343435335
712466055423135
oct1751415542453
9424863824585
10134422644011
1152010095027
1222075a55b4b
13c8a3235556
1467129da055
15376b27185b
hex1f4c36c52b

134422644011 has 4 divisors (see below), whose sum is σ = 134689886352. Its totient is φ = 134155401672.

The previous prime is 134422643977. The next prime is 134422644029. The reversal of 134422644011 is 110446224431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110446224431 = 532083891027.

It is a cyclic number.

It is not a de Polignac number, because 134422644011 - 218 = 134422381867 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134422644091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133620416 + ... + 133621421.

It is an arithmetic number, because the mean of its divisors is an integer number (33672471588).

Almost surely, 2134422644011 is an apocalyptic number.

134422644011 is a deficient number, since it is larger than the sum of its proper divisors (267242341).

134422644011 is an equidigital number, since it uses as much as digits as its factorization.

134422644011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267242340.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 134422644011 its reverse (110446224431), we get a palindrome (244868868442).

The spelling of 134422644011 in words is "one hundred thirty-four billion, four hundred twenty-two million, six hundred forty-four thousand, eleven".

Divisors: 1 503 267241837 134422644011