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134423124243 = 344807708081
BaseRepresentation
bin111110100110000111…
…1100001100100010011
3110211222011211020102020
41331030033201210103
54200244304433433
6141430402022523
712466062463212
oct1751417414423
9424864736366
10134423124243
1152010392911
1222076047a43
13c8a3373005
146712ac3079
15376b318cb3
hex1f4c3e1913

134423124243 has 4 divisors (see below), whose sum is σ = 179230832328. Its totient is φ = 89615416160.

The previous prime is 134423124233. The next prime is 134423124257. The reversal of 134423124243 is 342421324431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134423124243 - 25 = 134423124211 is a prime.

It is not an unprimeable number, because it can be changed into a prime (134423124223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22403854038 + ... + 22403854043.

It is an arithmetic number, because the mean of its divisors is an integer number (44807708082).

Almost surely, 2134423124243 is an apocalyptic number.

134423124243 is a deficient number, since it is larger than the sum of its proper divisors (44807708085).

134423124243 is an equidigital number, since it uses as much as digits as its factorization.

134423124243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44807708084.

The product of its digits is 55296, while the sum is 33.

Adding to 134423124243 its reverse (342421324431), we get a palindrome (476844448674).

The spelling of 134423124243 in words is "one hundred thirty-four billion, four hundred twenty-three million, one hundred twenty-four thousand, two hundred forty-three".

Divisors: 1 3 44807708081 134423124243