Base | Representation |
---|---|
bin | 1100001110011100101000… |
… | …1001101111010110001100 |
3 | 1202121002001002012011010101 |
4 | 3003213022021233112030 |
5 | 3230214410110020134 |
6 | 44331154440220444 |
7 | 2555114551420105 |
oct | 303471211572614 |
9 | 52532032164111 |
10 | 13442344220044 |
11 | 4312958964373 |
12 | 1611271a6a724 |
13 | 7667b8c3475c |
14 | 346881c553ac |
15 | 1849ed770e14 |
hex | c39ca26f58c |
13442344220044 has 12 divisors (see below), whose sum is σ = 24335278329600. Its totient is φ = 6489407554448.
The previous prime is 13442344219897. The next prime is 13442344220099. The reversal of 13442344220044 is 44002244324431.
13442344220044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13442344219985 and 13442344220012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57941138764 + ... + 57941138995.
It is an arithmetic number, because the mean of its divisors is an integer number (2027939860800).
Almost surely, 213442344220044 is an apocalyptic number.
It is an amenable number.
13442344220044 is a deficient number, since it is larger than the sum of its proper divisors (10892934109556).
13442344220044 is a wasteful number, since it uses less digits than its factorization.
13442344220044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115882277792 (or 115882277790 counting only the distinct ones).
The product of its (nonzero) digits is 294912, while the sum is 37.
Adding to 13442344220044 its reverse (44002244324431), we get a palindrome (57444588544475).
The spelling of 13442344220044 in words is "thirteen trillion, four hundred forty-two billion, three hundred forty-four million, two hundred twenty thousand, forty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •