13442400431531 has 2 divisors, whose sum is σ = 13442400431532. Its totient is φ = 13442400431530.

The previous prime is 13442400431521. The next prime is 13442400431569. The reversal of 13442400431531 is 13513400424431.

13442400431531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13442400431531 - 2¹⁰ = 13442400430507 is a prime.

It is a super-2 number, since 2×13442400431531² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13442400431491 and 13442400431500.

It is not a weakly prime, because it can be changed into another prime (13442400431521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721200215765 + 6721200215766.

It is an arithmetic number, because the mean of its divisors is an integer number (6721200215766).

Almost surely, 2^{13442400431531} is an apocalyptic number.

13442400431531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13442400431531 is an equidigital number, since it uses as much as digits as its factorization.

13442400431531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 13442400431531 its reverse (13513400424431), we get a palindrome (26955800855962).

The spelling of 13442400431531 in words is "thirteen trillion, four hundred forty-two billion, four hundred million, four hundred thirty-one thousand, five hundred thirty-one".