Base | Representation |
---|---|
bin | 1100001110011100110110… |
… | …0000100110101010000011 |
3 | 1202121002012000011210000002 |
4 | 3003213031200212222003 |
5 | 3230220014014423121 |
6 | 44331204211350215 |
7 | 2555116134241025 |
oct | 303471540465203 |
9 | 52532160153002 |
10 | 13442400545411 |
11 | 4312987735462 |
12 | 16112888b236b |
13 | 7667c77c5c86 |
14 | 346889518015 |
15 | 184a03699e0b |
hex | c39cd826a83 |
13442400545411 has 4 divisors (see below), whose sum is σ = 13442407879032. Its totient is φ = 13442393211792.
The previous prime is 13442400545401. The next prime is 13442400545423. The reversal of 13442400545411 is 11454500424431.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13442400545411 - 26 = 13442400545347 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13442400545401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1749956 + ... + 5472398.
It is an arithmetic number, because the mean of its divisors is an integer number (3360601969758).
Almost surely, 213442400545411 is an apocalyptic number.
13442400545411 is a deficient number, since it is larger than the sum of its proper divisors (7333621).
13442400545411 is an equidigital number, since it uses as much as digits as its factorization.
13442400545411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7333620.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 13442400545411 its reverse (11454500424431), we get a palindrome (24896900969842).
The spelling of 13442400545411 in words is "thirteen trillion, four hundred forty-two billion, four hundred million, five hundred forty-five thousand, four hundred eleven".
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