Base | Representation |
---|---|
bin | 10011100011111010111… |
… | …101100100101010010001 |
3 | 11202111201102011120021121 |
4 | 103203322331210222101 |
5 | 134011001000210142 |
6 | 2505311353322241 |
7 | 166055345344612 |
oct | 23437275445221 |
9 | 4674642146247 |
10 | 1344240241297 |
11 | 4790a8632288 |
12 | 198633406381 |
13 | 999b87a5005 |
14 | 490c0d65c09 |
15 | 24e77cd9c67 |
hex | 138faf64a91 |
1344240241297 has 2 divisors, whose sum is σ = 1344240241298. Its totient is φ = 1344240241296.
The previous prime is 1344240241291. The next prime is 1344240241339. The reversal of 1344240241297 is 7921420424431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 791181786256 + 553058455041 = 889484^2 + 743679^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344240241297 - 239 = 794484427409 is a prime.
It is not a weakly prime, because it can be changed into another prime (1344240241291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672120120648 + 672120120649.
It is an arithmetic number, because the mean of its divisors is an integer number (672120120649).
Almost surely, 21344240241297 is an apocalyptic number.
It is an amenable number.
1344240241297 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344240241297 is an equidigital number, since it uses as much as digits as its factorization.
1344240241297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 43.
The spelling of 1344240241297 in words is "one trillion, three hundred forty-four billion, two hundred forty million, two hundred forty-one thousand, two hundred ninety-seven".
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