13442413301131 has 4 divisors (see below), whose sum is σ = 13755027563992. Its totient is φ = 13129799038272.

The previous prime is 13442413301099. The next prime is 13442413301143. The reversal of 13442413301131 is 13110331424431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13442413301131 - 2⁵ = 13442413301099 is a prime.

It is a super-2 number, since 2×13442413301131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13442413301093 and 13442413301102.

It is not an unprimeable number, because it can be changed into a prime (13442413341131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156307131366 + ... + 156307131451.

It is an arithmetic number, because the mean of its divisors is an integer number (3438756890998).

Almost surely, 2^{13442413301131} is an apocalyptic number.

13442413301131 is a deficient number, since it is larger than the sum of its proper divisors (312614262861).

13442413301131 is an equidigital number, since it uses as much as digits as its factorization.

13442413301131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312614262860.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13442413301131 its reverse (13110331424431), we get a palindrome (26552744725562).

The spelling of 13442413301131 in words is "thirteen trillion, four hundred forty-two billion, four hundred thirteen million, three hundred one thousand, one hundred thirty-one".