Base | Representation |
---|---|
bin | 11001000010011110… |
… | …00111100111111010 |
3 | 1021200211110102201202 |
4 | 30201033013213322 |
5 | 210012240412102 |
6 | 10101515414202 |
7 | 654055323113 |
oct | 144117074772 |
9 | 37624412652 |
10 | 13442513402 |
11 | 5778a4830a |
12 | 2731a54362 |
13 | 1362c79b56 |
14 | 91743920a |
15 | 53a211e02 |
hex | 3213c79fa |
13442513402 has 4 divisors (see below), whose sum is σ = 20163770106. Its totient is φ = 6721256700.
The previous prime is 13442513389. The next prime is 13442513407. The reversal of 13442513402 is 20431524431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20431524431 = 37 ⋅552203363.
It can be written as a sum of positive squares in only one way, i.e., 10551192961 + 2891320441 = 102719^2 + 53771^2 .
It is a super-2 number, since 2×134425134022 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13442513407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3360628349 + ... + 3360628352.
Almost surely, 213442513402 is an apocalyptic number.
13442513402 is a deficient number, since it is larger than the sum of its proper divisors (6721256704).
13442513402 is an equidigital number, since it uses as much as digits as its factorization.
13442513402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6721256703.
The product of its (nonzero) digits is 11520, while the sum is 29.
The spelling of 13442513402 in words is "thirteen billion, four hundred forty-two million, five hundred thirteen thousand, four hundred two".
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