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1344252405193 is a prime number
BaseRepresentation
bin10011100011111011101…
…011111110010111001001
311202111202021001120000021
4103203323223332113021
5134011012103431233
62505312510140441
7166055553626065
oct23437353762711
94674667046007
101344252405193
11479104490195
121986374b1721
13999bb173799
14490c2810aa5
1524e78ddde2d
hex138fbafe5c9

1344252405193 has 2 divisors, whose sum is σ = 1344252405194. Its totient is φ = 1344252405192.

The previous prime is 1344252405179. The next prime is 1344252405233. The reversal of 1344252405193 is 3915042524431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 869645772304 + 474606632889 = 932548^2 + 688917^2 .

It is an emirp because it is prime and its reverse (3915042524431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344252405193 - 229 = 1343715534281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1344252405493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672126202596 + 672126202597.

It is an arithmetic number, because the mean of its divisors is an integer number (672126202597).

Almost surely, 21344252405193 is an apocalyptic number.

It is an amenable number.

1344252405193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344252405193 is an equidigital number, since it uses as much as digits as its factorization.

1344252405193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 43.

The spelling of 1344252405193 in words is "one trillion, three hundred forty-four billion, two hundred fifty-two million, four hundred five thousand, one hundred ninety-three".