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134430400513 is a prime number
BaseRepresentation
bin111110100110010101…
…1010010000000000001
3110211222200111220120201
41331030223102000001
54200303140304023
6141431222005201
712466211356633
oct1751453220001
9424880456521
10134430400513
1152014502662
1222078576801
13c8a4a1cbb6
146713a58a53
15376bca4bad
hex1f4cad2001

134430400513 has 2 divisors, whose sum is σ = 134430400514. Its totient is φ = 134430400512.

The previous prime is 134430400493. The next prime is 134430400519. The reversal of 134430400513 is 315004034431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131049792064 + 3380608449 = 362008^2 + 58143^2 .

It is an emirp because it is prime and its reverse (315004034431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134430400513 - 213 = 134430392321 is a prime.

It is not a weakly prime, because it can be changed into another prime (134430400519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67215200256 + 67215200257.

It is an arithmetic number, because the mean of its divisors is an integer number (67215200257).

Almost surely, 2134430400513 is an apocalyptic number.

It is an amenable number.

134430400513 is a deficient number, since it is larger than the sum of its proper divisors (1).

134430400513 is an equidigital number, since it uses as much as digits as its factorization.

134430400513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 134430400513 its reverse (315004034431), we get a palindrome (449434434944).

The spelling of 134430400513 in words is "one hundred thirty-four billion, four hundred thirty million, four hundred thousand, five hundred thirteen".