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134432043202034 = 2149451114238933
BaseRepresentation
bin11110100100001111100110…
…001011100111010111110010
3122121222120121020012200100022
4132210033212023213113302
5120110013311024431114
61153525121133123442
740213252231301654
oct3644174613472762
9577876536180308
10134432043202034
113991a34482a146
12130b19b7329582
135a01b6c476516
14252a78d20c6d4
151081d4511e48e
hex7a43e62e75f2

134432043202034 has 8 divisors (see below), whose sum is σ = 203001407520300. Its totient is φ = 66764907361936.

The previous prime is 134432043202021. The next prime is 134432043202073. The reversal of 134432043202034 is 430202340234431.

It can be written as a sum of positive squares in 2 ways, for example, as 96348889168009 + 38083154034025 = 9815747^2 + 6171155^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 134432043201985 and 134432043202003.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225557119169 + ... + 225557119764.

Almost surely, 2134432043202034 is an apocalyptic number.

134432043202034 is a deficient number, since it is larger than the sum of its proper divisors (68569364318266).

134432043202034 is a wasteful number, since it uses less digits than its factorization.

134432043202034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451114239084.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 134432043202034 its reverse (430202340234431), we get a palindrome (564634383436465).

The spelling of 134432043202034 in words is "one hundred thirty-four trillion, four hundred thirty-two billion, forty-three million, two hundred two thousand, thirty-four".

Divisors: 1 2 149 298 451114238933 902228477866 67216021601017 134432043202034