Base | Representation |
---|---|
bin | 11110100100001111100110… |
… | …001011100111010111110010 |
3 | 122121222120121020012200100022 |
4 | 132210033212023213113302 |
5 | 120110013311024431114 |
6 | 1153525121133123442 |
7 | 40213252231301654 |
oct | 3644174613472762 |
9 | 577876536180308 |
10 | 134432043202034 |
11 | 3991a34482a146 |
12 | 130b19b7329582 |
13 | 5a01b6c476516 |
14 | 252a78d20c6d4 |
15 | 1081d4511e48e |
hex | 7a43e62e75f2 |
134432043202034 has 8 divisors (see below), whose sum is σ = 203001407520300. Its totient is φ = 66764907361936.
The previous prime is 134432043202021. The next prime is 134432043202073. The reversal of 134432043202034 is 430202340234431.
It can be written as a sum of positive squares in 2 ways, for example, as 96348889168009 + 38083154034025 = 9815747^2 + 6171155^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 134432043201985 and 134432043202003.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225557119169 + ... + 225557119764.
Almost surely, 2134432043202034 is an apocalyptic number.
134432043202034 is a deficient number, since it is larger than the sum of its proper divisors (68569364318266).
134432043202034 is a wasteful number, since it uses less digits than its factorization.
134432043202034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 451114239084.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 134432043202034 its reverse (430202340234431), we get a palindrome (564634383436465).
The spelling of 134432043202034 in words is "one hundred thirty-four trillion, four hundred thirty-two billion, forty-three million, two hundred two thousand, thirty-four".
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