Base | Representation |
---|---|
bin | 11110100100001111110111… |
… | …101001100011100011101011 |
3 | 122121222121100122122201222002 |
4 | 132210033313221203203223 |
5 | 120110014411040412103 |
6 | 1153525210202321215 |
7 | 40213262420262203 |
oct | 3644176751434353 |
9 | 577877318581862 |
10 | 134432336263403 |
11 | 3991a4851a4522 |
12 | 130b1a794b920b |
13 | 5a01bb80b5009 |
14 | 252a7ba0d7403 |
15 | 1081d60c0c488 |
hex | 7a43f7a638eb |
134432336263403 has 2 divisors, whose sum is σ = 134432336263404. Its totient is φ = 134432336263402.
The previous prime is 134432336263391. The next prime is 134432336263523. The reversal of 134432336263403 is 304362633234431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134432336263403 - 228 = 134432067827947 is a prime.
It is not a weakly prime, because it can be changed into another prime (134432336260403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67216168131701 + 67216168131702.
It is an arithmetic number, because the mean of its divisors is an integer number (67216168131702).
Almost surely, 2134432336263403 is an apocalyptic number.
134432336263403 is a deficient number, since it is larger than the sum of its proper divisors (1).
134432336263403 is an equidigital number, since it uses as much as digits as its factorization.
134432336263403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 47.
Adding to 134432336263403 its reverse (304362633234431), we get a palindrome (438794969497834).
The spelling of 134432336263403 in words is "one hundred thirty-four trillion, four hundred thirty-two billion, three hundred thirty-six million, two hundred sixty-three thousand, four hundred three".
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