13443303111041 has 4 divisors (see below), whose sum is σ = 13443373919232. Its totient is φ = 13443232302852.

The previous prime is 13443303111037. The next prime is 13443303111059. The reversal of 13443303111041 is 14011130334431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13443303111041 - 2² = 13443303111037 is a prime.

It is a super-2 number, since 2×13443303111041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13443303110995 and 13443303111013.

It is not an unprimeable number, because it can be changed into a prime (13443303111011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35118545 + ... + 35499278.

It is an arithmetic number, because the mean of its divisors is an integer number (3360843479808).

Almost surely, 2^{13443303111041} is an apocalyptic number.

It is an amenable number.

13443303111041 is a deficient number, since it is larger than the sum of its proper divisors (70808191).

13443303111041 is an equidigital number, since it uses as much as digits as its factorization.

13443303111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70808190.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13443303111041 its reverse (14011130334431), we get a palindrome (27454433445472).

The spelling of 13443303111041 in words is "thirteen trillion, four hundred forty-three billion, three hundred three million, one hundred eleven thousand, forty-one".