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1344332660050 = 25226886653201
BaseRepresentation
bin10011100100000000011…
…110000111110101010010
311202111221212001220222101
4103210000132013311102
5134011143130110200
62505324454231014
7166060550033212
oct23440036076522
94674855056871
101344332660050
11479145815916
1219865a35546a
1399a01992b73
14490cd342242
1524e80e9326a
hex13900787d52

1344332660050 has 12 divisors (see below), whose sum is σ = 2500458747786. Its totient is φ = 537733064000.

The previous prime is 1344332659993. The next prime is 1344332660171. The reversal of 1344332660050 is 500662334431.

It can be written as a sum of positive squares in 3 ways, for example, as 1215380568249 + 128952091801 = 1102443^2 + 359099^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1344332659991 and 1344332660009.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13443326551 + ... + 13443326650.

Almost surely, 21344332660050 is an apocalyptic number.

1344332660050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1344332660050 is a deficient number, since it is larger than the sum of its proper divisors (1156126087736).

1344332660050 is a wasteful number, since it uses less digits than its factorization.

1344332660050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26886653213 (or 26886653208 counting only the distinct ones).

The product of its (nonzero) digits is 155520, while the sum is 37.

Adding to 1344332660050 its reverse (500662334431), we get a palindrome (1844994994481).

The spelling of 1344332660050 in words is "one trillion, three hundred forty-four billion, three hundred thirty-two million, six hundred sixty thousand, fifty".

Divisors: 1 2 5 10 25 50 26886653201 53773306402 134433266005 268866532010 672166330025 1344332660050