Base | Representation |
---|---|
bin | 101000000100001… |
… | …0000001000111001 |
3 | 10110200121120112021 |
4 | 1100020100020321 |
5 | 10223122344122 |
6 | 341221514441 |
7 | 45212464111 |
oct | 12010201071 |
9 | 3420546467 |
10 | 1344340537 |
11 | 62a932a41 |
12 | 316272a21 |
13 | 185691397 |
14 | ca784041 |
15 | 7d04d1c7 |
hex | 50210239 |
1344340537 has 2 divisors, whose sum is σ = 1344340538. Its totient is φ = 1344340536.
The previous prime is 1344340523. The next prime is 1344340541. The reversal of 1344340537 is 7350434431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 826505001 + 517835536 = 28749^2 + 22756^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344340537 is a prime.
It is not a weakly prime, because it can be changed into another prime (1344340507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672170268 + 672170269.
It is an arithmetic number, because the mean of its divisors is an integer number (672170269).
Almost surely, 21344340537 is an apocalyptic number.
It is an amenable number.
1344340537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344340537 is an equidigital number, since it uses as much as digits as its factorization.
1344340537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 34.
The square root of 1344340537 is about 36665.2497195914. The cubic root of 1344340537 is about 1103.6628686103.
Adding to 1344340537 its reverse (7350434431), we get a palindrome (8694774968).
The spelling of 1344340537 in words is "one billion, three hundred forty-four million, three hundred forty thousand, five hundred thirty-seven".
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