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134434061123 is a prime number
BaseRepresentation
bin111110100110011100…
…1001111101101000011
3110211222221101212222212
41331030321033231003
54200310104423443
6141431432252335
712466254444155
oct1751471175503
9424887355885
10134434061123
115201658295a
12220798410ab
13c8a570213b
14671432cad5
15376c279618
hex1f4ce4fb43

134434061123 has 2 divisors, whose sum is σ = 134434061124. Its totient is φ = 134434061122.

The previous prime is 134434061063. The next prime is 134434061137. The reversal of 134434061123 is 321160434431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134434061123 - 212 = 134434057027 is a prime.

It is a super-2 number, since 2×1344340611232 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134434061123.

It is not a weakly prime, because it can be changed into another prime (134434061143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67217030561 + 67217030562.

It is an arithmetic number, because the mean of its divisors is an integer number (67217030562).

Almost surely, 2134434061123 is an apocalyptic number.

134434061123 is a deficient number, since it is larger than the sum of its proper divisors (1).

134434061123 is an equidigital number, since it uses as much as digits as its factorization.

134434061123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 134434061123 its reverse (321160434431), we get a palindrome (455594495554).

The spelling of 134434061123 in words is "one hundred thirty-four billion, four hundred thirty-four million, sixty-one thousand, one hundred twenty-three".