Base | Representation |
---|---|
bin | 10011100100000000111… |
… | …100100110110100101100 |
3 | 11202111222102002220220220 |
4 | 103210000330212310230 |
5 | 134011202201320213 |
6 | 2505325341411340 |
7 | 166061004665304 |
oct | 23440074466454 |
9 | 4674872086826 |
10 | 1344340651308 |
11 | 47914a283866 |
12 | 198660b69b50 |
13 | 99a03530315 |
14 | 490d0422604 |
15 | 24e81a20e23 |
hex | 13900f26d2c |
1344340651308 has 48 divisors (see below), whose sum is σ = 3160085676384. Its totient is φ = 444787107840.
The previous prime is 1344340651301. The next prime is 1344340651319. The reversal of 1344340651308 is 8031560434431.
It is a super-2 number, since 2×13443406513082 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1344340651308.
It is not an unprimeable number, because it can be changed into a prime (1344340651301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14356416 + ... + 14449752.
It is an arithmetic number, because the mean of its divisors is an integer number (65835118258).
Almost surely, 21344340651308 is an apocalyptic number.
It is an amenable number.
1344340651308 is an abundant number, since it is smaller than the sum of its proper divisors (1815745025076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1344340651308 is a wasteful number, since it uses less digits than its factorization.
1344340651308 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102242 (or 102240 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 42.
The spelling of 1344340651308 in words is "one trillion, three hundred forty-four billion, three hundred forty million, six hundred fifty-one thousand, three hundred eight".
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