Base | Representation |
---|---|
bin | 111110100110011101… |
… | …0100111011011010001 |
3 | 110211222222002010212122 |
4 | 1331030322213123101 |
5 | 4200310202423213 |
6 | 141431444104025 |
7 | 12466260501545 |
oct | 1751472473321 |
9 | 424888063778 |
10 | 134434420433 |
11 | 520167a8905 |
12 | 22079995015 |
13 | c8a57c9851 |
14 | 67143c3a25 |
15 | 376c2ead08 |
hex | 1f4cea76d1 |
134434420433 has 2 divisors, whose sum is σ = 134434420434. Its totient is φ = 134434420432.
The previous prime is 134434420391. The next prime is 134434420487. The reversal of 134434420433 is 334024434431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 134038728769 + 395691664 = 366113^2 + 19892^2 .
It is a cyclic number.
It is not a de Polignac number, because 134434420433 - 26 = 134434420369 is a prime.
It is a super-2 number, since 2×1344344204332 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134434420393 and 134434420402.
It is not a weakly prime, because it can be changed into another prime (134454420433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67217210216 + 67217210217.
It is an arithmetic number, because the mean of its divisors is an integer number (67217210217).
Almost surely, 2134434420433 is an apocalyptic number.
It is an amenable number.
134434420433 is a deficient number, since it is larger than the sum of its proper divisors (1).
134434420433 is an equidigital number, since it uses as much as digits as its factorization.
134434420433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 134434420433 its reverse (334024434431), we get a palindrome (468458854864).
The spelling of 134434420433 in words is "one hundred thirty-four billion, four hundred thirty-four million, four hundred twenty thousand, four hundred thirty-three".
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