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134434420433 is a prime number
BaseRepresentation
bin111110100110011101…
…0100111011011010001
3110211222222002010212122
41331030322213123101
54200310202423213
6141431444104025
712466260501545
oct1751472473321
9424888063778
10134434420433
11520167a8905
1222079995015
13c8a57c9851
1467143c3a25
15376c2ead08
hex1f4cea76d1

134434420433 has 2 divisors, whose sum is σ = 134434420434. Its totient is φ = 134434420432.

The previous prime is 134434420391. The next prime is 134434420487. The reversal of 134434420433 is 334024434431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134038728769 + 395691664 = 366113^2 + 19892^2 .

It is a cyclic number.

It is not a de Polignac number, because 134434420433 - 26 = 134434420369 is a prime.

It is a super-2 number, since 2×1344344204332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134434420393 and 134434420402.

It is not a weakly prime, because it can be changed into another prime (134454420433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67217210216 + 67217210217.

It is an arithmetic number, because the mean of its divisors is an integer number (67217210217).

Almost surely, 2134434420433 is an apocalyptic number.

It is an amenable number.

134434420433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134434420433 is an equidigital number, since it uses as much as digits as its factorization.

134434420433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 134434420433 its reverse (334024434431), we get a palindrome (468458854864).

The spelling of 134434420433 in words is "one hundred thirty-four billion, four hundred thirty-four million, four hundred twenty thousand, four hundred thirty-three".