Base | Representation |
---|---|
bin | 11110100100010111010100… |
… | …000111011001001110111011 |
3 | 122122000100222202100200022021 |
4 | 132210113110013121032323 |
5 | 120110132243442242001 |
6 | 1153533011320535311 |
7 | 40213664464253104 |
oct | 3644272407311673 |
9 | 578010882320267 |
10 | 134440330040251 |
11 | 39922907501374 |
12 | 130b352a621537 |
13 | 5a028902596a1 |
14 | 252ad37a213ab |
15 | 108217c8c8ba1 |
hex | 7a45d41d93bb |
134440330040251 has 4 divisors (see below), whose sum is σ = 136446902130472. Its totient is φ = 132433757950032.
The previous prime is 134440330040249. The next prime is 134440330040297. The reversal of 134440330040251 is 152040033044431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134440330040251 - 21 = 134440330040249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134440330040551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003286045010 + ... + 1003286045143.
It is an arithmetic number, because the mean of its divisors is an integer number (34111725532618).
Almost surely, 2134440330040251 is an apocalyptic number.
134440330040251 is a deficient number, since it is larger than the sum of its proper divisors (2006572090221).
134440330040251 is an equidigital number, since it uses as much as digits as its factorization.
134440330040251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2006572090220.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 134440330040251 its reverse (152040033044431), we get a palindrome (286480363084682).
The spelling of 134440330040251 in words is "one hundred thirty-four trillion, four hundred forty billion, three hundred thirty million, forty thousand, two hundred fifty-one".
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