Base | Representation |
---|---|
bin | 10011100100000101001… |
… | …001111000111001100001 |
3 | 11202112011022221022020222 |
4 | 103210011021320321201 |
5 | 134011323234221311 |
6 | 2505340342412425 |
7 | 166062523002305 |
oct | 23440511707141 |
9 | 4675138838228 |
10 | 1344411242081 |
11 | 479186108746 |
12 | 198680731115 |
13 | 99a150479cb |
14 | 490d9959d05 |
15 | 24e87d16adb |
hex | 13905278e61 |
1344411242081 has 2 divisors, whose sum is σ = 1344411242082. Its totient is φ = 1344411242080.
The previous prime is 1344411241993. The next prime is 1344411242107. The reversal of 1344411242081 is 1802421144431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1182960769600 + 161450472481 = 1087640^2 + 401809^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344411242081 - 226 = 1344344133217 is a prime.
It is a super-2 number, since 2×13444112420812 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1344411245081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672205621040 + 672205621041.
It is an arithmetic number, because the mean of its divisors is an integer number (672205621041).
Almost surely, 21344411242081 is an apocalyptic number.
It is an amenable number.
1344411242081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344411242081 is an equidigital number, since it uses as much as digits as its factorization.
1344411242081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24576, while the sum is 35.
The spelling of 1344411242081 in words is "one trillion, three hundred forty-four billion, four hundred eleven million, two hundred forty-two thousand, eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •