1344413400041 has 2 divisors, whose sum is σ = 1344413400042. Its totient is φ = 1344413400040.

The previous prime is 1344413400013. The next prime is 1344413400061. The reversal of 1344413400041 is 1400043144431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1298754257641 + 45659142400 = 1139629^2 + 213680^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344413400041 - 2²⁶ = 1344346291177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1344413399977 and 1344413400013.

It is not a weakly prime, because it can be changed into another prime (1344413400061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672206700020 + 672206700021.

It is an arithmetic number, because the mean of its divisors is an integer number (672206700021).

Almost surely, 2^{1344413400041} is an apocalyptic number.

It is an amenable number.

1344413400041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344413400041 is an equidigital number, since it uses as much as digits as its factorization.

1344413400041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 1344413400041 its reverse (1400043144431), we get a palindrome (2744456544472).

The spelling of 1344413400041 in words is "one trillion, three hundred forty-four billion, four hundred thirteen million, four hundred thousand, forty-one".