Base | Representation |
---|---|
bin | 10011100100000101010… |
… | …010001010100000001011 |
3 | 11202112011111000111220212 |
4 | 103210011102022200023 |
5 | 134011324313130324 |
6 | 2505340501111335 |
7 | 166062550305545 |
oct | 23440522124013 |
9 | 4675144014825 |
10 | 1344413411339 |
11 | 47918735a519 |
12 | 1986813b854b |
13 | 99a156271ab |
14 | 490d9d62695 |
15 | 24e880e470e |
hex | 1390548a80b |
1344413411339 has 2 divisors, whose sum is σ = 1344413411340. Its totient is φ = 1344413411338.
The previous prime is 1344413411333. The next prime is 1344413411377. The reversal of 1344413411339 is 9331143144431.
It is a weak prime.
It is an emirp because it is prime and its reverse (9331143144431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1344413411339 - 232 = 1340118444043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1344413411296 and 1344413411305.
It is not a weakly prime, because it can be changed into another prime (1344413411333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672206705669 + 672206705670.
It is an arithmetic number, because the mean of its divisors is an integer number (672206705670).
Almost surely, 21344413411339 is an apocalyptic number.
1344413411339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344413411339 is an equidigital number, since it uses as much as digits as its factorization.
1344413411339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 186624, while the sum is 41.
The spelling of 1344413411339 in words is "one trillion, three hundred forty-four billion, four hundred thirteen million, four hundred eleven thousand, three hundred thirty-nine".
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