Base | Representation |
---|---|
bin | 11001000010101010… |
… | …11100001110010011 |
3 | 1021200221120122001001 |
4 | 30201111130032103 |
5 | 210013201430033 |
6 | 10102015122431 |
7 | 654105364531 |
oct | 144125341623 |
9 | 37627518031 |
10 | 13444170643 |
11 | 577997a432 |
12 | 2732513417 |
13 | 136340a277 |
14 | 91774b151 |
15 | 53a43ce7d |
hex | 32155c393 |
13444170643 has 2 divisors, whose sum is σ = 13444170644. Its totient is φ = 13444170642.
The previous prime is 13444170587. The next prime is 13444170647. The reversal of 13444170643 is 34607144431.
It is a strong prime.
It is an emirp because it is prime and its reverse (34607144431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13444170643 - 213 = 13444162451 is a prime.
It is not a weakly prime, because it can be changed into another prime (13444170647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722085321 + 6722085322.
It is an arithmetic number, because the mean of its divisors is an integer number (6722085322).
Almost surely, 213444170643 is an apocalyptic number.
13444170643 is a deficient number, since it is larger than the sum of its proper divisors (1).
13444170643 is an equidigital number, since it uses as much as digits as its factorization.
13444170643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 37.
The spelling of 13444170643 in words is "thirteen billion, four hundred forty-four million, one hundred seventy thousand, six hundred forty-three".
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