Base | Representation |
---|---|
bin | 111110100110101110… |
… | …1010110010000000001 |
3 | 110212000121012201011022 |
4 | 1331031131112100001 |
5 | 4200320020300441 |
6 | 141432411155225 |
7 | 12466431052043 |
oct | 1751535262001 |
9 | 425017181138 |
10 | 134443525121 |
11 | 52020957344 |
12 | 22080a45b15 |
13 | c8a7666a39 |
14 | 67156b3a93 |
15 | 376cee884b |
hex | 1f4d756401 |
134443525121 has 8 divisors (see below), whose sum is σ = 135539342400. Its totient is φ = 133350411600.
The previous prime is 134443525103. The next prime is 134443525159. The reversal of 134443525121 is 121525344431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134443525121 is a prime.
It is a super-2 number, since 2×1344435251212 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134445525121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 576026 + ... + 775043.
It is an arithmetic number, because the mean of its divisors is an integer number (16942417800).
Almost surely, 2134443525121 is an apocalyptic number.
It is an amenable number.
134443525121 is a deficient number, since it is larger than the sum of its proper divisors (1095817279).
134443525121 is a wasteful number, since it uses less digits than its factorization.
134443525121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1351879.
The product of its digits is 57600, while the sum is 35.
Adding to 134443525121 its reverse (121525344431), we get a palindrome (255968869552).
The spelling of 134443525121 in words is "one hundred thirty-four billion, four hundred forty-three million, five hundred twenty-five thousand, one hundred twenty-one".
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