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134444021433 = 31720939125897
BaseRepresentation
bin111110100110101111…
…1001111011010111001
3110212000122010220222020
41331031133033122321
54200320132141213
6141432425545053
712466435220031
oct1751537173271
9425018126866
10134444021433
1152021166217
1222081045189
13c8a77ab907
1467157a28c1
15376d095923
hex1f4d7cf6b9

134444021433 has 16 divisors (see below), whose sum is σ = 189813896640. Its totient is φ = 84352334336.

The previous prime is 134444021423. The next prime is 134444021441. The reversal of 134444021433 is 334120444431.

It is a cyclic number.

It is not a de Polignac number, because 134444021433 - 225 = 134410467001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134444021394 and 134444021403.

It is not an unprimeable number, because it can be changed into a prime (134444021423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1004941 + ... + 1130837.

It is an arithmetic number, because the mean of its divisors is an integer number (11863368540).

Almost surely, 2134444021433 is an apocalyptic number.

It is an amenable number.

134444021433 is a deficient number, since it is larger than the sum of its proper divisors (55369875207).

134444021433 is a wasteful number, since it uses less digits than its factorization.

134444021433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146856.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 134444021433 its reverse (334120444431), we get a palindrome (468564465864).

The spelling of 134444021433 in words is "one hundred thirty-four billion, four hundred forty-four million, twenty-one thousand, four hundred thirty-three".

Divisors: 1 3 17 51 20939 62817 125897 355963 377691 1067889 2140249 6420747 2636157283 7908471849 44814673811 134444021433