Base | Representation |
---|---|
bin | 11001000010101100… |
… | …11101111001111010 |
3 | 1021200222002022002011 |
4 | 30201112131321322 |
5 | 210013234032144 |
6 | 10102025000134 |
7 | 654110565061 |
oct | 144126357172 |
9 | 37628068064 |
10 | 13444439674 |
11 | 577a043576 |
12 | 273262304a |
13 | 13634a2863 |
14 | 9177bb1d8 |
15 | 53a492a34 |
hex | 32159de7a |
13444439674 has 4 divisors (see below), whose sum is σ = 20166659514. Its totient is φ = 6722219836.
The previous prime is 13444439663. The next prime is 13444439707. The reversal of 13444439674 is 47693444431.
13444439674 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6747472449 + 6696967225 = 82143^2 + 81835^2 .
It is a Smith number, since the sum of its digits (49) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3361109917 + ... + 3361109920.
Almost surely, 213444439674 is an apocalyptic number.
13444439674 is a deficient number, since it is larger than the sum of its proper divisors (6722219840).
13444439674 is an equidigital number, since it uses as much as digits as its factorization.
13444439674 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6722219839.
The product of its digits is 3483648, while the sum is 49.
The spelling of 13444439674 in words is "thirteen billion, four hundred forty-four million, four hundred thirty-nine thousand, six hundred seventy-four".
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