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134450041106153 is a prime number
BaseRepresentation
bin11110100100100000010110…
…111100001010111011101001
3122122001022001112102221100202
4132210200112330022323221
5120110312141010344103
61153541255102441545
740214460233044433
oct3644402674127351
9578038045387322
10134450041106153
1139926a4010a973
12130b539a8932b5
135a0377a121b26
14252b5b9651653
15108254a211988
hex7a4816f0aee9

134450041106153 has 2 divisors, whose sum is σ = 134450041106154. Its totient is φ = 134450041106152.

The previous prime is 134450041106119. The next prime is 134450041106189. The reversal of 134450041106153 is 351601140054431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133634709762304 + 815331343849 = 11560048^2 + 902957^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134450041106153 is a prime.

It is not a weakly prime, because it can be changed into another prime (134450041100153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67225020553076 + 67225020553077.

It is an arithmetic number, because the mean of its divisors is an integer number (67225020553077).

Almost surely, 2134450041106153 is an apocalyptic number.

It is an amenable number.

134450041106153 is a deficient number, since it is larger than the sum of its proper divisors (1).

134450041106153 is an equidigital number, since it uses as much as digits as its factorization.

134450041106153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 38.

The spelling of 134450041106153 in words is "one hundred thirty-four trillion, four hundred fifty billion, forty-one million, one hundred six thousand, one hundred fifty-three".