Base | Representation |
---|---|
bin | 11110100100100000010110… |
… | …111100001010111011101001 |
3 | 122122001022001112102221100202 |
4 | 132210200112330022323221 |
5 | 120110312141010344103 |
6 | 1153541255102441545 |
7 | 40214460233044433 |
oct | 3644402674127351 |
9 | 578038045387322 |
10 | 134450041106153 |
11 | 39926a4010a973 |
12 | 130b539a8932b5 |
13 | 5a0377a121b26 |
14 | 252b5b9651653 |
15 | 108254a211988 |
hex | 7a4816f0aee9 |
134450041106153 has 2 divisors, whose sum is σ = 134450041106154. Its totient is φ = 134450041106152.
The previous prime is 134450041106119. The next prime is 134450041106189. The reversal of 134450041106153 is 351601140054431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 133634709762304 + 815331343849 = 11560048^2 + 902957^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134450041106153 is a prime.
It is not a weakly prime, because it can be changed into another prime (134450041100153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67225020553076 + 67225020553077.
It is an arithmetic number, because the mean of its divisors is an integer number (67225020553077).
Almost surely, 2134450041106153 is an apocalyptic number.
It is an amenable number.
134450041106153 is a deficient number, since it is larger than the sum of its proper divisors (1).
134450041106153 is an equidigital number, since it uses as much as digits as its factorization.
134450041106153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 134450041106153 in words is "one hundred thirty-four trillion, four hundred fifty billion, forty-one million, one hundred six thousand, one hundred fifty-three".
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