Base | Representation |
---|---|
bin | 11110100100100100001011… |
… | …010010001100111000110001 |
3 | 122122001200122020012211202112 |
4 | 132210210023102030320301 |
5 | 120110344034433201113 |
6 | 1153543213543255105 |
7 | 40214663641361303 |
oct | 3644441322147061 |
9 | 578050566184675 |
10 | 134454140522033 |
11 | 39928754126782 |
12 | 130b614374a495 |
13 | 5a03c815111b7 |
14 | 252b887c83973 |
15 | 10826da0735a8 |
hex | 7a490b48ce31 |
134454140522033 has 2 divisors, whose sum is σ = 134454140522034. Its totient is φ = 134454140522032.
The previous prime is 134454140521973. The next prime is 134454140522069. The reversal of 134454140522033 is 330225041454431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132310542927424 + 2143597594609 = 11502632^2 + 1464103^2 .
It is a cyclic number.
It is not a de Polignac number, because 134454140522033 - 26 = 134454140521969 is a prime.
It is not a weakly prime, because it can be changed into another prime (134454140522083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67227070261016 + 67227070261017.
It is an arithmetic number, because the mean of its divisors is an integer number (67227070261017).
Almost surely, 2134454140522033 is an apocalyptic number.
It is an amenable number.
134454140522033 is a deficient number, since it is larger than the sum of its proper divisors (1).
134454140522033 is an equidigital number, since it uses as much as digits as its factorization.
134454140522033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 134454140522033 its reverse (330225041454431), we get a palindrome (464679181976464).
The spelling of 134454140522033 in words is "one hundred thirty-four trillion, four hundred fifty-four billion, one hundred forty million, five hundred twenty-two thousand, thirty-three".
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