Base | Representation |
---|---|
bin | 1100001110101000011010… |
… | …0100011011000000001011 |
3 | 1202121101012101101020102202 |
4 | 3003222012210123000023 |
5 | 3230242343331044321 |
6 | 44332440241550415 |
7 | 2555256104420462 |
oct | 303520644330013 |
9 | 52541171336382 |
10 | 13445505331211 |
11 | 4314230265a38 |
12 | 16119b464540b |
13 | 766ba0b08435 |
14 | 346aa19d99d9 |
15 | 184b3603b70b |
hex | c3a8691b00b |
13445505331211 has 2 divisors, whose sum is σ = 13445505331212. Its totient is φ = 13445505331210.
The previous prime is 13445505331207. The next prime is 13445505331267. The reversal of 13445505331211 is 11213350554431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13445505331211 - 22 = 13445505331207 is a prime.
It is a super-2 number, since 2×134455053312112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13445505331411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722752665605 + 6722752665606.
It is an arithmetic number, because the mean of its divisors is an integer number (6722752665606).
Almost surely, 213445505331211 is an apocalyptic number.
13445505331211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13445505331211 is an equidigital number, since it uses as much as digits as its factorization.
13445505331211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 13445505331211 its reverse (11213350554431), we get a palindrome (24658855885642).
The spelling of 13445505331211 in words is "thirteen trillion, four hundred forty-five billion, five hundred five million, three hundred thirty-one thousand, two hundred eleven".
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