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13445551155121 is a prime number
BaseRepresentation
bin1100001110101000100101…
…0011001110011110110001
31202121101022120121100000121
43003222021103032132301
53230242442043430441
644332445000050241
72555260202053051
oct303521123163661
952541276540017
1013445551155121
114314254114138
121611a07a63981
13766baa460a87
14346aa7b27561
15184b3a08ddd1
hexc3a894ce7b1

13445551155121 has 2 divisors, whose sum is σ = 13445551155122. Its totient is φ = 13445551155120.

The previous prime is 13445551155017. The next prime is 13445551155149. The reversal of 13445551155121 is 12155115554431.

13445551155121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8416027279521 + 5029523875600 = 2901039^2 + 2242660^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13445551155121 is a prime.

It is not a weakly prime, because it can be changed into another prime (13445551155151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722775577560 + 6722775577561.

It is an arithmetic number, because the mean of its divisors is an integer number (6722775577561).

Almost surely, 213445551155121 is an apocalyptic number.

It is an amenable number.

13445551155121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13445551155121 is an equidigital number, since it uses as much as digits as its factorization.

13445551155121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 300000, while the sum is 43.

The spelling of 13445551155121 in words is "thirteen trillion, four hundred forty-five billion, five hundred fifty-one million, one hundred fifty-five thousand, one hundred twenty-one".