Base | Representation |
---|---|
bin | 11001000011000001… |
… | …10000110101111001 |
3 | 1021201011011102102101 |
4 | 30201200300311321 |
5 | 210014431414211 |
6 | 10102202503401 |
7 | 654142535644 |
oct | 144140606571 |
9 | 37634142371 |
10 | 13447138681 |
11 | 5780617359 |
12 | 2733504b61 |
13 | 1363c091c2 |
14 | 917cc0a5b |
15 | 53a8275c1 |
hex | 321830d79 |
13447138681 has 2 divisors, whose sum is σ = 13447138682. Its totient is φ = 13447138680.
The previous prime is 13447138643. The next prime is 13447138693. The reversal of 13447138681 is 18683174431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13362204025 + 84934656 = 115595^2 + 9216^2 .
It is an emirp because it is prime and its reverse (18683174431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13447138681 - 233 = 4857204089 is a prime.
It is a super-2 number, since 2×134471386812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13447138381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6723569340 + 6723569341.
It is an arithmetic number, because the mean of its divisors is an integer number (6723569341).
Almost surely, 213447138681 is an apocalyptic number.
It is an amenable number.
13447138681 is a deficient number, since it is larger than the sum of its proper divisors (1).
13447138681 is an equidigital number, since it uses as much as digits as its factorization.
13447138681 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 387072, while the sum is 46.
The spelling of 13447138681 in words is "thirteen billion, four hundred forty-seven million, one hundred thirty-eight thousand, six hundred eighty-one".
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