Base | Representation |
---|---|
bin | 10011100100101110100… |
… | …000110100101110010011 |
3 | 11202120221200120222000121 |
4 | 103210232200310232103 |
5 | 134014233402321042 |
6 | 2505533250531111 |
7 | 166115646605365 |
oct | 23445640645623 |
9 | 4676850528017 |
10 | 1345105120147 |
11 | 479501856598 |
12 | 198834b96a97 |
13 | 99ac5a22749 |
14 | 49163b7cd35 |
15 | 24ec8bca367 |
hex | 1392e834b93 |
1345105120147 has 2 divisors, whose sum is σ = 1345105120148. Its totient is φ = 1345105120146.
The previous prime is 1345105120109. The next prime is 1345105120273. The reversal of 1345105120147 is 7410215015431.
It is a weak prime.
It is an emirp because it is prime and its reverse (7410215015431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1345105120147 - 239 = 795349306259 is a prime.
It is not a weakly prime, because it can be changed into another prime (1345105120547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672552560073 + 672552560074.
It is an arithmetic number, because the mean of its divisors is an integer number (672552560074).
Almost surely, 21345105120147 is an apocalyptic number.
1345105120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345105120147 is an equidigital number, since it uses as much as digits as its factorization.
1345105120147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 1345105120147 in words is "one trillion, three hundred forty-five billion, one hundred five million, one hundred twenty thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •