1345114020163 has 4 divisors (see below), whose sum is σ = 1345201670800. Its totient is φ = 1345026369528.

The previous prime is 1345114020143. The next prime is 1345114020179. The reversal of 1345114020163 is 3610204115431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1345114020163 - 2¹³ = 1345114011971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1345114020143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43802295 + ... + 43832992.

It is an arithmetic number, because the mean of its divisors is an integer number (336300417700).

Almost surely, 2^{1345114020163} is an apocalyptic number.

1345114020163 is a deficient number, since it is larger than the sum of its proper divisors (87650637).

1345114020163 is an equidigital number, since it uses as much as digits as its factorization.

1345114020163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87650636.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 1345114020163 its reverse (3610204115431), we get a palindrome (4955318135594).

The spelling of 1345114020163 in words is "one trillion, three hundred forty-five billion, one hundred fourteen million, twenty thousand, one hundred sixty-three".